blob: 3e811873618ab17bc09dedae731c689f2321e5da [file] [log] [blame]
package org.apache.lucene.search;
/*
* Licensed to the Apache Software Foundation (ASF) under one or more
* contributor license agreements. See the NOTICE file distributed with
* this work for additional information regarding copyright ownership.
* The ASF licenses this file to You under the Apache License, Version 2.0
* (the "License"); you may not use this file except in compliance with
* the License. You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*/
import java.io.IOException;
import java.util.ArrayList;
import java.util.Collection;
import java.util.Comparator;
import org.apache.lucene.util.ArrayUtil;
/** Scorer for conjunctions, sets of queries, all of which are required. */
class ConjunctionScorer extends Scorer {
protected int lastDoc = -1;
protected final DocsAndFreqs[] docsAndFreqs;
private final DocsAndFreqs lead;
private final float coord;
ConjunctionScorer(Weight weight, Scorer[] scorers) {
this(weight, scorers, 1f);
}
ConjunctionScorer(Weight weight, Scorer[] scorers, float coord) {
super(weight);
this.coord = coord;
this.docsAndFreqs = new DocsAndFreqs[scorers.length];
for (int i = 0; i < scorers.length; i++) {
docsAndFreqs[i] = new DocsAndFreqs(scorers[i]);
}
// Sort the array the first time to allow the least frequent DocsEnum to
// lead the matching.
ArrayUtil.timSort(docsAndFreqs, new Comparator<DocsAndFreqs>() {
@Override
public int compare(DocsAndFreqs o1, DocsAndFreqs o2) {
return Long.compare(o1.cost, o2.cost);
}
});
lead = docsAndFreqs[0]; // least frequent DocsEnum leads the intersection
}
private int doNext(int doc) throws IOException {
for(;;) {
// doc may already be NO_MORE_DOCS here, but we don't check explicitly
// since all scorers should advance to NO_MORE_DOCS, match, then
// return that value.
advanceHead: for(;;) {
for (int i = 1; i < docsAndFreqs.length; i++) {
// invariant: docsAndFreqs[i].doc <= doc at this point.
// docsAndFreqs[i].doc may already be equal to doc if we "broke advanceHead"
// on the previous iteration and the advance on the lead scorer exactly matched.
if (docsAndFreqs[i].doc < doc) {
docsAndFreqs[i].doc = docsAndFreqs[i].scorer.advance(doc);
if (docsAndFreqs[i].doc > doc) {
// DocsEnum beyond the current doc - break and advance lead to the new highest doc.
doc = docsAndFreqs[i].doc;
break advanceHead;
}
}
}
// success - all DocsEnums are on the same doc
return doc;
}
// advance head for next iteration
doc = lead.doc = lead.scorer.advance(doc);
}
}
@Override
public int advance(int target) throws IOException {
lead.doc = lead.scorer.advance(target);
return lastDoc = doNext(lead.doc);
}
@Override
public int docID() {
return lastDoc;
}
@Override
public int nextDoc() throws IOException {
lead.doc = lead.scorer.nextDoc();
return lastDoc = doNext(lead.doc);
}
@Override
public float score() throws IOException {
// TODO: sum into a double and cast to float if we ever send required clauses to BS1
float sum = 0.0f;
for (DocsAndFreqs docs : docsAndFreqs) {
sum += docs.scorer.score();
}
return sum * coord;
}
@Override
public int freq() {
return docsAndFreqs.length;
}
@Override
public long cost() {
return lead.scorer.cost();
}
@Override
public Collection<ChildScorer> getChildren() {
ArrayList<ChildScorer> children = new ArrayList<>(docsAndFreqs.length);
for (DocsAndFreqs docs : docsAndFreqs) {
children.add(new ChildScorer(docs.scorer, "MUST"));
}
return children;
}
static final class DocsAndFreqs {
final long cost;
final Scorer scorer;
int doc = -1;
DocsAndFreqs(Scorer scorer) {
this.scorer = scorer;
this.cost = scorer.cost();
}
}
}